Self._execute_child(args, executable, preexec_fn, close_fds,įile "/Users/srcomp1/Downloads/Xcode.app/Contents/Developer/Library/Frameworks/amework/Versions/3.8/lib/python3.8/subprocess. Self.build_environment = BuildEnvironment(įile "/Users/srcomp1/Downloads/Telegram-iOS-release-7.6/build-system/Make/BuildEnvironment.py", line 123, in _init_Īctual_bazel_version = get_bazel_version(self.bazel_path)įile "/Users/srcomp1/Downloads/Telegram-iOS-release-7.6/build-system/Make/BuildEnvironment.py", line 66, in get_bazel_versionĬommand_result = run_executable_with_output(bazel_path, ).strip('\n')įile "/Users/srcomp1/Downloads/Telegram-iOS-release-7.6/build-system/Make/BuildEnvironment.py", line 36, in run_executable_with_outputįile "/Users/srcomp1/Downloads/Xcode.app/Contents/Developer/Library/Frameworks/amework/Versions/3.8/lib/python3.8/subprocess.py", line 854, in _init_ I am seeing this error Traceback (most recent call last):įile "build-system/Make/Make.py", line 560, in įile "build-system/Make/Make.py", line 339, in generate_projectįile "build-system/Make/Make.py", line 16, in _init_ Apparently Telegram bought an alternative client called Challegram which they acquired and turned into Telegram X. configurationPath="$HOME/telegram-configuration" \ When i try to generate the XCode project, python3 build-system/Make/Make.py \
I have tried it with Telegram 7.6 and 7.8 and behaviour is same. Steps mentioned below and have installed Bazel and yasm
I am trying to build the latest Telegram IOS app for my Simulator but I am getting a python error.I have followed all the
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